Integrand size = 29, antiderivative size = 491 \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)} \, dx=\frac {\left (c d^2-b d e+a e^2\right ) \sqrt {a+b x+c x^2}}{e^2 (e f-d g)}-\frac {\left (4 c e f^2-g (5 b e f-b d g-4 a e g)-2 c g (e f-d g) x\right ) \sqrt {a+b x+c x^2}}{4 e g^2 (e f-d g)}-\frac {(2 c d-b e) \left (c d^2-b d e+a e^2\right ) \text {arctanh}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right )}{2 \sqrt {c} e^3 (e f-d g)}+\frac {\left (8 c^2 e f^3+b g^2 (3 b e f+b d g-4 a e g)-4 c g \left (3 b e f^2-a g (3 e f-d g)\right )\right ) \text {arctanh}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right )}{8 \sqrt {c} e g^3 (e f-d g)}+\frac {\left (c d^2-b d e+a e^2\right )^{3/2} \text {arctanh}\left (\frac {b d-2 a e+(2 c d-b e) x}{2 \sqrt {c d^2-b d e+a e^2} \sqrt {a+b x+c x^2}}\right )}{e^3 (e f-d g)}-\frac {\left (c f^2-b f g+a g^2\right )^{3/2} \text {arctanh}\left (\frac {b f-2 a g+(2 c f-b g) x}{2 \sqrt {c f^2-b f g+a g^2} \sqrt {a+b x+c x^2}}\right )}{g^3 (e f-d g)} \]
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Time = 0.50 (sec) , antiderivative size = 491, normalized size of antiderivative = 1.00, number of steps used = 13, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.241, Rules used = {909, 748, 857, 635, 212, 738, 828} \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)} \, dx=\frac {\text {arctanh}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right ) \left (-4 c g \left (3 b e f^2-a g (3 e f-d g)\right )+b g^2 (-4 a e g+b d g+3 b e f)+8 c^2 e f^3\right )}{8 \sqrt {c} e g^3 (e f-d g)}+\frac {\left (a e^2-b d e+c d^2\right )^{3/2} \text {arctanh}\left (\frac {-2 a e+x (2 c d-b e)+b d}{2 \sqrt {a+b x+c x^2} \sqrt {a e^2-b d e+c d^2}}\right )}{e^3 (e f-d g)}-\frac {(2 c d-b e) \text {arctanh}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right ) \left (a e^2-b d e+c d^2\right )}{2 \sqrt {c} e^3 (e f-d g)}-\frac {\left (a g^2-b f g+c f^2\right )^{3/2} \text {arctanh}\left (\frac {-2 a g+x (2 c f-b g)+b f}{2 \sqrt {a+b x+c x^2} \sqrt {a g^2-b f g+c f^2}}\right )}{g^3 (e f-d g)}+\frac {\sqrt {a+b x+c x^2} \left (a e^2-b d e+c d^2\right )}{e^2 (e f-d g)}-\frac {\sqrt {a+b x+c x^2} \left (-g (-4 a e g-b d g+5 b e f)-2 c g x (e f-d g)+4 c e f^2\right )}{4 e g^2 (e f-d g)} \]
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Rule 212
Rule 635
Rule 738
Rule 748
Rule 828
Rule 857
Rule 909
Rubi steps \begin{align*} \text {integral}& = -\frac {\int \frac {(c d f-b e f+a e g-c (e f-d g) x) \sqrt {a+b x+c x^2}}{f+g x} \, dx}{e (e f-d g)}+\frac {\left (c d^2-b d e+a e^2\right ) \int \frac {\sqrt {a+b x+c x^2}}{d+e x} \, dx}{e (e f-d g)} \\ & = \frac {\left (c d^2-b d e+a e^2\right ) \sqrt {a+b x+c x^2}}{e^2 (e f-d g)}-\frac {\left (4 c e f^2-g (5 b e f-b d g-4 a e g)-2 c g (e f-d g) x\right ) \sqrt {a+b x+c x^2}}{4 e g^2 (e f-d g)}-\frac {\left (c d^2-b d e+a e^2\right ) \int \frac {b d-2 a e+(2 c d-b e) x}{(d+e x) \sqrt {a+b x+c x^2}} \, dx}{2 e^2 (e f-d g)}+\frac {\int \frac {\frac {1}{2} c \left (f \left (4 b c f-b^2 g-4 a c g\right ) (e f-d g)+4 g (b f-2 a g) (c d f-b e f+a e g)\right )+\frac {1}{2} c \left (8 c^2 e f^3+b g^2 (3 b e f+b d g-4 a e g)-4 c g \left (3 b e f^2-a g (3 e f-d g)\right )\right ) x}{(f+g x) \sqrt {a+b x+c x^2}} \, dx}{4 c e g^2 (e f-d g)} \\ & = \frac {\left (c d^2-b d e+a e^2\right ) \sqrt {a+b x+c x^2}}{e^2 (e f-d g)}-\frac {\left (4 c e f^2-g (5 b e f-b d g-4 a e g)-2 c g (e f-d g) x\right ) \sqrt {a+b x+c x^2}}{4 e g^2 (e f-d g)}-\frac {\left ((2 c d-b e) \left (c d^2-b d e+a e^2\right )\right ) \int \frac {1}{\sqrt {a+b x+c x^2}} \, dx}{2 e^3 (e f-d g)}+\frac {\left (c d^2-b d e+a e^2\right )^2 \int \frac {1}{(d+e x) \sqrt {a+b x+c x^2}} \, dx}{e^3 (e f-d g)}-\frac {\left (c f^2-b f g+a g^2\right )^2 \int \frac {1}{(f+g x) \sqrt {a+b x+c x^2}} \, dx}{g^3 (e f-d g)}+\frac {\left (8 c^2 e f^3+b g^2 (3 b e f+b d g-4 a e g)-4 c g \left (3 b e f^2-a g (3 e f-d g)\right )\right ) \int \frac {1}{\sqrt {a+b x+c x^2}} \, dx}{8 e g^3 (e f-d g)} \\ & = \frac {\left (c d^2-b d e+a e^2\right ) \sqrt {a+b x+c x^2}}{e^2 (e f-d g)}-\frac {\left (4 c e f^2-g (5 b e f-b d g-4 a e g)-2 c g (e f-d g) x\right ) \sqrt {a+b x+c x^2}}{4 e g^2 (e f-d g)}-\frac {\left ((2 c d-b e) \left (c d^2-b d e+a e^2\right )\right ) \text {Subst}\left (\int \frac {1}{4 c-x^2} \, dx,x,\frac {b+2 c x}{\sqrt {a+b x+c x^2}}\right )}{e^3 (e f-d g)}-\frac {\left (2 \left (c d^2-b d e+a e^2\right )^2\right ) \text {Subst}\left (\int \frac {1}{4 c d^2-4 b d e+4 a e^2-x^2} \, dx,x,\frac {-b d+2 a e-(2 c d-b e) x}{\sqrt {a+b x+c x^2}}\right )}{e^3 (e f-d g)}+\frac {\left (2 \left (c f^2-b f g+a g^2\right )^2\right ) \text {Subst}\left (\int \frac {1}{4 c f^2-4 b f g+4 a g^2-x^2} \, dx,x,\frac {-b f+2 a g-(2 c f-b g) x}{\sqrt {a+b x+c x^2}}\right )}{g^3 (e f-d g)}+\frac {\left (8 c^2 e f^3+b g^2 (3 b e f+b d g-4 a e g)-4 c g \left (3 b e f^2-a g (3 e f-d g)\right )\right ) \text {Subst}\left (\int \frac {1}{4 c-x^2} \, dx,x,\frac {b+2 c x}{\sqrt {a+b x+c x^2}}\right )}{4 e g^3 (e f-d g)} \\ & = \frac {\left (c d^2-b d e+a e^2\right ) \sqrt {a+b x+c x^2}}{e^2 (e f-d g)}-\frac {\left (4 c e f^2-g (5 b e f-b d g-4 a e g)-2 c g (e f-d g) x\right ) \sqrt {a+b x+c x^2}}{4 e g^2 (e f-d g)}-\frac {(2 c d-b e) \left (c d^2-b d e+a e^2\right ) \tanh ^{-1}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right )}{2 \sqrt {c} e^3 (e f-d g)}+\frac {\left (8 c^2 e f^3+b g^2 (3 b e f+b d g-4 a e g)-4 c g \left (3 b e f^2-a g (3 e f-d g)\right )\right ) \tanh ^{-1}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+b x+c x^2}}\right )}{8 \sqrt {c} e g^3 (e f-d g)}+\frac {\left (c d^2-b d e+a e^2\right )^{3/2} \tanh ^{-1}\left (\frac {b d-2 a e+(2 c d-b e) x}{2 \sqrt {c d^2-b d e+a e^2} \sqrt {a+b x+c x^2}}\right )}{e^3 (e f-d g)}-\frac {\left (c f^2-b f g+a g^2\right )^{3/2} \tanh ^{-1}\left (\frac {b f-2 a g+(2 c f-b g) x}{2 \sqrt {c f^2-b f g+a g^2} \sqrt {a+b x+c x^2}}\right )}{g^3 (e f-d g)} \\ \end{align*}
Time = 10.72 (sec) , antiderivative size = 323, normalized size of antiderivative = 0.66 \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)} \, dx=\frac {\frac {\left (3 b^2 e^2 g^2-12 c e g (b e f+b d g-a e g)+8 c^2 \left (e^2 f^2+d e f g+d^2 g^2\right )\right ) \text {arctanh}\left (\frac {b+2 c x}{2 \sqrt {c} \sqrt {a+x (b+c x)}}\right )}{\sqrt {c}}+\frac {2 \left (e g (e f-d g) \sqrt {a+x (b+c x)} (5 b e g+c (-4 e f-4 d g+2 e g x))-4 \left (c d^2+e (-b d+a e)\right )^{3/2} g^3 \text {arctanh}\left (\frac {-b d+2 a e-2 c d x+b e x}{2 \sqrt {c d^2+e (-b d+a e)} \sqrt {a+x (b+c x)}}\right )+4 e^3 \left (c f^2+g (-b f+a g)\right )^{3/2} \text {arctanh}\left (\frac {-b f+2 a g-2 c f x+b g x}{2 \sqrt {c f^2+g (-b f+a g)} \sqrt {a+x (b+c x)}}\right )\right )}{e f-d g}}{8 e^3 g^3} \]
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Time = 0.82 (sec) , antiderivative size = 599, normalized size of antiderivative = 1.22
method | result | size |
risch | \(\frac {\left (2 c e g x +5 b e g -4 c d g -4 c e f \right ) \sqrt {c \,x^{2}+b x +a}}{4 e^{2} g^{2}}+\frac {\frac {\left (12 a c \,e^{2} g^{2}+3 b^{2} e^{2} g^{2}-12 b c d e \,g^{2}-12 b c \,e^{2} f g +8 c^{2} d^{2} g^{2}+8 c^{2} d e f g +8 c^{2} e^{2} f^{2}\right ) \ln \left (\frac {\frac {b}{2}+c x}{\sqrt {c}}+\sqrt {c \,x^{2}+b x +a}\right )}{e g \sqrt {c}}+\frac {8 g^{2} \left (a^{2} e^{4}-2 a b d \,e^{3}+2 a c \,d^{2} e^{2}+b^{2} d^{2} e^{2}-2 b c \,d^{3} e +c^{2} d^{4}\right ) \ln \left (\frac {\frac {2 e^{2} a -2 b d e +2 c \,d^{2}}{e^{2}}+\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+2 \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}\, \sqrt {\left (x +\frac {d}{e}\right )^{2} c +\frac {\left (b e -2 c d \right ) \left (x +\frac {d}{e}\right )}{e}+\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}{x +\frac {d}{e}}\right )}{e^{2} \left (d g -e f \right ) \sqrt {\frac {e^{2} a -b d e +c \,d^{2}}{e^{2}}}}-\frac {8 e^{2} \left (a^{2} g^{4}-2 a b f \,g^{3}+2 a c \,f^{2} g^{2}+b^{2} f^{2} g^{2}-2 b c \,f^{3} g +c^{2} f^{4}\right ) \ln \left (\frac {\frac {2 a \,g^{2}-2 b f g +2 c \,f^{2}}{g^{2}}+\frac {\left (b g -2 c f \right ) \left (x +\frac {f}{g}\right )}{g}+2 \sqrt {\frac {a \,g^{2}-b f g +c \,f^{2}}{g^{2}}}\, \sqrt {\left (x +\frac {f}{g}\right )^{2} c +\frac {\left (b g -2 c f \right ) \left (x +\frac {f}{g}\right )}{g}+\frac {a \,g^{2}-b f g +c \,f^{2}}{g^{2}}}}{x +\frac {f}{g}}\right )}{g^{2} \left (d g -e f \right ) \sqrt {\frac {a \,g^{2}-b f g +c \,f^{2}}{g^{2}}}}}{8 e^{2} g^{2}}\) | \(599\) |
default | \(\text {Expression too large to display}\) | \(1265\) |
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Timed out. \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)} \, dx=\text {Timed out} \]
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\[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)} \, dx=\int \frac {\left (a + b x + c x^{2}\right )^{\frac {3}{2}}}{\left (d + e x\right ) \left (f + g x\right )}\, dx \]
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Exception generated. \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)} \, dx=\text {Exception raised: ValueError} \]
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Exception generated. \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)} \, dx=\text {Exception raised: TypeError} \]
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Timed out. \[ \int \frac {\left (a+b x+c x^2\right )^{3/2}}{(d+e x) (f+g x)} \, dx=\int \frac {{\left (c\,x^2+b\,x+a\right )}^{3/2}}{\left (f+g\,x\right )\,\left (d+e\,x\right )} \,d x \]
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